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Message-ID: <20250512183742.28fad543@kernel.org>
Date: Mon, 12 May 2025 18:37:42 -0700
From: Jakub Kicinski <kuba@...nel.org>
To: Antonio Quartulli <antonio@...nvpn.net>
Cc: netdev@...r.kernel.org, Eric Dumazet <edumazet@...gle.com>, Paolo Abeni
<pabeni@...hat.com>, Sabrina Dubroca <sd@...asysnail.net>, Al Viro
<viro@...iv.linux.org.uk>, Qingfang Deng <dqfext@...il.com>, Gert Doering
<gert@...enie.muc.de>
Subject: Re: [PATCH net-next 10/10] ovpn: ensure sk is still valid during
cleanup
On Fri, 9 May 2025 16:26:20 +0200 Antonio Quartulli wrote:
> In case of UDP peer timeout, an openvpn client (userspace)
> performs the following actions:
> 1. receives the peer deletion notification (reason=timeout)
> 2. closes the socket
>
> Upon 1. we have the following:
> - ovpn_peer_keepalive_work()
> - ovpn_socket_release()
> - synchronize_rcu()
> At this point, 2. gets a chance to complete and ovpn_sock->sock->sk
> becomes NULL. ovpn_socket_release() will then attempt dereferencing it,
> resulting in the following crash log:
What runs where is a bit unclear to me. Specifically I'm not sure what
runs the code under the "if (released)" branch of ovpn_socket_release()
if the user closes the socket. Because you now return without a WARN().
> @@ -75,13 +76,14 @@ void ovpn_socket_release(struct ovpn_peer *peer)
> if (!sock)
> return;
>
> - /* sanity check: we should not end up here if the socket
> - * was already closed
> + /* sock->sk may be released concurrently, therefore we
> + * first attempt grabbing a reference.
> + * if sock->sk is NULL it means it is already being
> + * destroyed and we don't need any further cleanup
> */
> - if (!sock->sock->sk) {
> - DEBUG_NET_WARN_ON_ONCE(1);
> + sk = sock->sock->sk;
> + if (!sk || !refcount_inc_not_zero(&sk->sk_refcnt))
How is sk protected from getting reused here?
refcount_inc_not_zero() still needs the underlying object to be allocated.
I don't see any locking here, and code says this function may sleep so
it can't be called under RCU, either.
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