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Message-ID: <CALW8-7L16VUNPMgf9rm6qusUMt=dW=KryY_EmMWoM_NnVmzhsw@mail.gmail.com>
Date: Wed, 23 Apr 2014 16:29:49 +0200
From: Dmitry Khovratovich <khovratovich@...il.com>
To: "discussions@...sword-hashing.net" <discussions@...sword-hashing.net>
Subject: Re: [PHC] Dumb fast file digest idea...

I think that collisions for this hash function can be found by differential
cryptanalysis, where differences are injected in block[0], block[1], and
block[128*128-1]. The first two compensate each other in the state, and the
third one cancels the difference in buffer[0].


On Wed, Apr 23, 2014 at 4:03 PM, Bill Cox <waywardgeek@...il.com> wrote:

> On Wed, Apr 23, 2014 at 9:31 AM, Dmitry Khovratovich <
> khovratovich@...il.com> wrote:
>
>> Hi Bill,
>>
>> If you alternate AES rounds with message injection on the full state,
>> collisions can be found instantly.
>>
>> It is a non-trivial task to make a secure AES-based hash function, and
>> there have been many attempts during the SHA-3 competition. All of them are
>> not that fast.  One of problems is that the 128-bit state can provide only
>> 64-bit security against collision attacks, which is certainly not
>> recommended.
>>
>
> I see.  Blake2b should still be a decent candidate for the lower level
> primitive, providing up to 256 bits of collision resistance?
>
>
>> I do not understand what you're doing in the last two paragraphs. A
>> pseudocode would help.
>>
>> Bets regards,
>> Dmitry
>>
>
> The code, without parallel lanes or dealing with the last partial block,
> or optimizing memory accesses, would look something like:
>
> blockSize = 64*128*128 // 1 MiB buffer
> uint512 block[128*128]
> uint512 state = 0
> while(block = readBlockFromFile(file)) {
>     state = hashBlock(block, state)
> }
> output state // Digest of file
>
> hashBlock(uint512 block[128*128], uint512 state) {
>     uint512 buffer[128*128]
>     for(i = 0; i < 128; i++) {
>         for(j = 0; j < 128; j++) {
>             state = Blake2B_ROUND(state, block[i*128+j])
>             buffer[i + j*128] = state // Note that we multiply j, not i by
> 128
>         }
>     }
>     for(i = 0; i < 128*128; i++) {
>         state = Blake2B_ROUND(state, buffer[i])
>     }
>     return state
> }
>
> In this case, Blake2b_ROUND would be something like Lyra2's modified
> Blake2b round, where the state and 512 bits of input are XORed together
> before doing just the one round.  I incorrectly stated that Blake2b uses 8
> rounds above.  It normally uses 12.  This version would use only 2.
>
> By writing non-cryptographically strong single-round hashes separated by
> long distances in memory, and then doing an outer hash of the memory,
> adjacent memory locations should not be at all correlated.  Wont this allow
> a cryptographically strong hash be derived from the buffer using only 1
> round per 512-bit location in the buffer?  Of course, I'm very often
> wrong...
>
> Bill
>



-- 
Best regards,
Dmitry Khovratovich

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