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Date:	Tue, 16 Oct 2007 15:00:27 +0530
From:	Balbir Singh <balbir@...ux.vnet.ibm.com>
To:	Christian Borntraeger <borntraeger@...ibm.com>
CC:	Chuck Ebbert <cebbert@...hat.com>, Frans Pop <elendil@...net.nl>,
	Greg KH <greg@...ah.com>, stable@...nel.org,
	linux-kernel@...r.kernel.org, Ingo Molnar <mingo@...e.hu>
Subject: Re: [stable] 2.6.23 regression: top displaying 9999% CPU usage

Christian Borntraeger wrote:
> Chuck, Balbir,
> 
> we still have a problem with stime occosionally going backwards. I stated
> below that I think this is not fixable with the current utime/stime split
> algorithm.
> 

Hi,

I missed seeing this problem before, sorry about that. Thanks for the
link below, I now understand the problem.

> Balbir, you wrote this code, Chuck you tried to fix it. Any ideas how to
> fix this properly? The only idea I have requires that we save the old value
> of utime and stime and therefore requires additional locking.
> 

I am trying to think out loud as to what the root cause of the problem
might be. In one of the discussion threads, I saw utime going backwards,
which seemed very odd, I suspect that those are rounding errors.

I don't understand your explanation below

Initially utime = 9, stime = 0, sum_exec_runtime = S1

Later

utime = 9, stime = 1, sum_exec_runtime = S2

We can be sure that S >= (utime + stime)

If S2 = S1 + delta, then as per our calculation

Initially

utime_proc = (utime * (S1))/(utime + stime)
           = nsec_to_clock_t(9 * S1 / 9)

later

utime_proc = nsec_to_clock_t(9 * S2/10)

Given that S >= (utime + stime), we should be fine.
The only problem I see is with rounding, like I mentioned before at two
places

1. Rounding at do_div() in task_utime()
2. Rounding in conversion from clock_t_to_cputime()

I have tried and not had any success reproducing the problem, could you
please help me with some pointers/steps to reproduce the problem?

-- 
	Warm Regards,
	Balbir Singh
	Linux Technology Center
	IBM, ISTL
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