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Message-ID: <491A7345.4090500@linux.vnet.ibm.com>
Date:	Wed, 12 Nov 2008 11:40:13 +0530
From:	Balbir Singh <balbir@...ux.vnet.ibm.com>
To:	KAMEZAWA Hiroyuki <kamezawa.hiroyu@...fujitsu.com>
CC:	linux-mm@...ck.org, YAMAMOTO Takashi <yamamoto@...inux.co.jp>,
	Paul Menage <menage@...gle.com>, lizf@...fujitsu.com,
	linux-kernel@...r.kernel.org,
	Nick Piggin <nickpiggin@...oo.com.au>,
	David Rientjes <rientjes@...gle.com>,
	Pavel Emelianov <xemul@...nvz.org>,
	Dhaval Giani <dhaval@...ux.vnet.ibm.com>,
	Andrew Morton <akpm@...ux-foundation.org>
Subject: Re: [RFC][mm] [PATCH 3/4] Memory cgroup hierarchical reclaim (v3)

KAMEZAWA Hiroyuki wrote:
> On Wed, 12 Nov 2008 11:19:37 +0530
> Balbir Singh <balbir@...ux.vnet.ibm.com> wrote:
> 
>> KAMEZAWA Hiroyuki wrote:
>>> On Tue, 11 Nov 2008 18:04:17 +0530
>>> Balbir Singh <balbir@...ux.vnet.ibm.com> wrote:
>>>
>>>> This patch introduces hierarchical reclaim. When an ancestor goes over its
>>>> limit, the charging routine points to the parent that is above its limit.
>>>> The reclaim process then starts from the last scanned child of the ancestor
>>>> and reclaims until the ancestor goes below its limit.
>>>>
>>>> +/*
>>>> + * Dance down the hierarchy if needed to reclaim memory. We remember the
>>>> + * last child we reclaimed from, so that we don't end up penalizing
>>>> + * one child extensively based on its position in the children list.
>>>> + *
>>>> + * root_mem is the original ancestor that we've been reclaim from.
>>>> + */
>>>> +static int mem_cgroup_hierarchical_reclaim(struct mem_cgroup *mem,
>>>> +						struct mem_cgroup *root_mem,
>>>> +						gfp_t gfp_mask)
>>>> +{
>>>> +	struct cgroup *cg_current, *cgroup;
>>>> +	struct mem_cgroup *mem_child;
>>>> +	int ret = 0;
>>>> +
>>>> +	/*
>>>> +	 * Reclaim unconditionally and don't check for return value.
>>>> +	 * We need to reclaim in the current group and down the tree.
>>>> +	 * One might think about checking for children before reclaiming,
>>>> +	 * but there might be left over accounting, even after children
>>>> +	 * have left.
>>>> +	 */
>>>> +	try_to_free_mem_cgroup_pages(mem, gfp_mask);
>>>> +
>>>> +	if (res_counter_check_under_limit(&root_mem->res))
>>>> +		return 0;
>>>> +
>>>> +	cgroup_lock();
>>>> +
>>>> +	if (list_empty(&mem->css.cgroup->children)) {
>>>> +		cgroup_unlock();
>>>> +		return 0;
>>>> +	}
>>>> +
>>>> +	/*
>>>> +	 * Scan all children under the mem_cgroup mem
>>>> +	 */
>>>> +	if (!mem->last_scanned_child)
>>>> +		cgroup = list_first_entry(&mem->css.cgroup->children,
>>>> +				struct cgroup, sibling);
>>>> +	else
>>>> +		cgroup = mem->last_scanned_child->css.cgroup;
>>>> +
>>>> +	cg_current = cgroup;
>>>> +
>>>> +	do {
>>>> +		struct list_head *next;
>>>> +
>>>> +		mem_child = mem_cgroup_from_cont(cgroup);
>>>> +		cgroup_unlock();
>>>> +
>>>> +		ret = mem_cgroup_hierarchical_reclaim(mem_child, root_mem,
>>>> +							gfp_mask);
>>>> +		cgroup_lock();
>>>> +		mem->last_scanned_child = mem_child;
>>>> +		if (res_counter_check_under_limit(&root_mem->res)) {
>>>> +			ret = 0;
>>>> +			goto done;
>>>> +		}
>>>> +
>>>> +		/*
>>>> +		 * Since we gave up the lock, it is time to
>>>> +		 * start from last cgroup
>>>> +		 */
>>>> +		cgroup = mem->last_scanned_child->css.cgroup;
>>>> +		next = cgroup->sibling.next;
>>>> +
>>>> +		if (next == &cg_current->parent->children)
>>>> +			cgroup = list_first_entry(&mem->css.cgroup->children,
>>>> +							struct cgroup, sibling);
>>>> +		else
>>>> +			cgroup = container_of(next, struct cgroup, sibling);
>>>> +	} while (cgroup != cg_current);
>>>> +
>>>> +done:
>>>> +	cgroup_unlock();
>>>> +	return ret;
>>>> +}
>>> Hmm, does this function is necessary to be complex as this ?
>>> I'm sorry I don't have enough time to review now. (chasing memory online/offline bug.)
>>>
>>> But I can't convice this is a good way to reclaim in hierachical manner.
>>>
>>> In following tree, Assume that processes hit limitation of Level_2.
>>>
>>>    Level_1 (no limit)
>>> 	-> Level_2	(limit=1G)
>>> 		-> Level_3_A (usage=30M)
>>> 		-> Level_3_B (usage=100M)
>>> 			-> Level_4_A (usage=50M)
>>> 			-> Level_4_B (usage=400M)
>>> 			-> Level_4_C (usage=420M)
>>>
>>> Even if we know Level_4_C incudes tons of Inactive file caches,
>>> some amount of swap-out will occur until reachin Level_4_C.
>>>
>>> Can't we do this hierarchical reclaim in another way ?
>>> (start from Level_4_C because we know it has tons of inactive caches.)
>>>
>>> This style of recursive call doesn't have chance to do kind of optimization.
>>> Can we do this reclaim in more flat manner as loop like following
>>> =
>>> try:
>>>   select the most inactive one
>>> 	-> try_to_fre_memory
>>> 		-> check limit
>>> 			-> go to try;
>>> ==
>>>
>> I've been thinking along those lines as well and that will get more important as
>> we try to implement soft limits. However, for the current version I wanted
>> correctness. Fairness, I've seen is achieved, since groups with large number of
>> inactive pages, does get reclaimed from more than others (in my simple
>> experiments).
>>
>> As far the pseudo code is concerned, select the most inactive one is an O(c)
>> operation, where c is the number of nodes under the subtree and is expensive.
>> The data structure and select algorithm get expensive. I am thinking about a
>> more suitable approach for implementation, but I want to focus on correctness as
>> the first step. Since the hierarchy is not enabled by default, I am not adding
>> any additional overhead, so I think that this approach is suitable.
>>
> What I say here is not "implement fairness" but "please make this algorithm easy
> to be updated." If you'll implement soft-limit, please design this code to be
> easily reused. (Again, I don't say do it now but please make code simpler.)
> 

I think of it as easy to update - as in the modularity, you can plug out
hierarchical reclaim easily and implement your own hierarchical reclaim.

> Can you make this code iterative rather than recursive ?
> 
> I don't like this kind of recursive call with complexed lock/unlock.

I tried an iterative version, which ended up looking very ugly. I think the
recursive version is easier to understand. What we do is a DFS walk - pretty
standard algorithm.

-- 
	Balbir
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