linux-kernel - Re: [take2] OOM documentation update [was: Linux killed Kenny, bastard!]

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Message-ID: <3e8340490901141353u3990148ft1b20220a8317f7dc@mail.gmail.com>
Date:	Wed, 14 Jan 2009 16:53:16 -0500
From:	"Bryan Donlan" <bdonlan@...il.com>
To:	"Evgeniy Polyakov" <zbr@...emap.net>
Cc:	linux-kernel@...r.kernel.org,
	"David Rientjes" <rientjes@...gle.com>,
	"Balbir Singh" <balbir@...ux.vnet.ibm.com>,
	"Alan Cox" <alan@...rguk.ukuu.org.uk>,
	"Dave Jones" <davej@...hat.com>,
	"Andrew Morton" <akpm@...ux-foundation.org>,
	"Linus Torvalds" <torvalds@...ux-foundation.org>,
	"Theodore Tso" <tytso@....edu>,
	"Matthias Andree" <matthias.andree@....de>
Subject: Re: [take2] OOM documentation update [was: Linux killed Kenny, bastard!]

On Wed, Jan 14, 2009 at 12:06 PM, Evgeniy Polyakov <zbr@...emap.net> wrote:

> + * resulted score is multiplied by the two in the power of oom_adj when it is
> +       positive, and divided otherwise, i.e.
> +       points <<= oom_adj when it is positive and
> +       points >>= oom_adj otherwise

Two to the power of a negative number is equivalent to dividing by two
to the power of said exponent's absolute value, making this paragraph
more than a bit confusing - indeed, a literal read would make it
equivalent to multiplying by 2^abs(oom_adj).

I would think that the following would be enough:
* The resulting score is multiplied by two to the power of oom_adj.

Unless we assume admins don't know how exponentiation by a negative
number works :)
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