linux-kernel - Re: [take2] OOM documentation update [was: Linux killed Kenny, bastard!]

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Message-ID: <20090114221043.GA6039@ioremap.net>
Date:	Thu, 15 Jan 2009 01:10:44 +0300
From:	Evgeniy Polyakov <zbr@...emap.net>
To:	Bryan Donlan <bdonlan@...il.com>
Cc:	linux-kernel@...r.kernel.org, David Rientjes <rientjes@...gle.com>,
	Balbir Singh <balbir@...ux.vnet.ibm.com>,
	Alan Cox <alan@...rguk.ukuu.org.uk>,
	Dave Jones <davej@...hat.com>,
	Andrew Morton <akpm@...ux-foundation.org>,
	Linus Torvalds <torvalds@...ux-foundation.org>,
	Theodore Tso <tytso@....edu>,
	Matthias Andree <matthias.andree@....de>
Subject: Re: [take2] OOM documentation update [was: Linux killed Kenny, bastard!]

On Wed, Jan 14, 2009 at 04:53:16PM -0500, Bryan Donlan (bdonlan@...il.com) wrote:
> On Wed, Jan 14, 2009 at 12:06 PM, Evgeniy Polyakov <zbr@...emap.net> wrote:
> 
> > + * resulted score is multiplied by the two in the power of oom_adj when it is
> > +       positive, and divided otherwise, i.e.
> > +       points <<= oom_adj when it is positive and
> > +       points >>= oom_adj otherwise
> 
> Two to the power of a negative number is equivalent to dividing by two
> to the power of said exponent's absolute value, making this paragraph
> more than a bit confusing - indeed, a literal read would make it
> equivalent to multiplying by 2^abs(oom_adj).
> 
> I would think that the following would be enough:
> * The resulting score is multiplied by two to the power of oom_adj.

Yes, I think it is enough with shift example.

Thanks guys I will update the doc.

-- 
	Evgeniy Polyakov
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