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Message-ID: <1264102455.31321.293.camel@gandalf.stny.rr.com>
Date: Thu, 21 Jan 2010 14:34:15 -0500
From: Steven Rostedt <rostedt@...dmis.org>
To: David Daney <ddaney@...iumnetworks.com>
Cc: LKML <linux-kernel@...r.kernel.org>,
kernel-janitors <kernel-janitors@...r.kernel.org>,
Peter Zijlstra <peterz@...radead.org>,
Andrew Morton <akpm@...ux-foundation.org>,
linux-arch@...r.kernel.org, Greg KH <greg@...ah.com>,
Andy Whitcroft <apw@...onical.com>,
Ralf Baechle <ralf@...ux-mips.org>,
linux-mips <linux-mips@...ux-mips.org>
Subject: Re: Lots of bugs with current->state = TASK_*INTERRUPTIBLE
On Thu, 2010-01-21 at 11:18 -0800, David Daney wrote:
> Steven Rostedt wrote:
> > Peter Zijlstra and I were doing a look over of places that assign
> > current->state = TASK_*INTERRUPTIBLE, by simply looking at places with:
> >
> > $ git grep -A1 'state[[:space:]]*=[[:space:]]*TASK_[^R]'
> >
> > and it seems there are quite a few places that looks like bugs. To be on
> > the safe side, everything outside of a run queue lock that sets the
> > current state to something other than TASK_RUNNING (or dead) should be
> > using set_current_state().
> >
> > current->state = TASK_INTERRUPTIBLE;
> > schedule();
> >
> > is probably OK, but it would not hurt to be consistent. Here's a few
> > examples of likely bugs:
> >
> [...]
>
> This may be a bit off topic, but exactly which type of barrier should
> set_current_state() be implying?
>
> On MIPS, set_mb() (which is used by set_current_state()) has a full mb().
>
> Some MIPS based processors have a much lighter weight wmb(). Could
> wmb() be used in place of mb() here?
Nope, wmb() is not enough. Below is an explanation.
>
> If not, an explanation of the required memory ordering semantics here
> would be appreciated.
>
> I know the documentation says:
>
> set_current_state() includes a barrier so that the write of
> current->state is correctly serialised wrt the caller's subsequent
> test of whether to actually sleep:
>
> set_current_state(TASK_UNINTERRUPTIBLE);
> if (do_i_need_to_sleep())
> schedule();
>
>
> Since the current CPU sees the memory accesses in order, what can be
> happening on other CPUs that would require a full mb()?
Lets look at a hypothetical situation with:
add_wait_queue();
current->state = TASK_UNINTERRUPTIBLE;
smp_wmb();
if (!x)
schedule();
Then somewhere we probably have:
x = 1;
smp_wmb();
wake_up(queue);
CPU 0 CPU 1
------------ -----------
add_wait_queue();
(cpu pipeline sees a load
of x ahead, and preloads it)
x = 1;
smp_wmb();
wake_up(queue);
(task on CPU 0 is still at
TASK_RUNNING);
current->state = TASK_INTERRUPTIBLE;
smp_wmb(); <<-- does not prevent early loading of x
if (!x) <<-- returns true
schedule();
Now the task on CPU 0 missed the wake up.
Note, places that call schedule() are not fast paths, and probably not
called often. Adding the overhead of smp_mb() to ensure correctness is a
small price to pay compared to search for why you have a stuck task that
was never woken up.
Read Documentation/memory-barriers.txt, it will be worth the time you
spend doing so.
-- Steve
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