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Message-ID: <20120802103244.GA23318@leaf>
Date: Thu, 2 Aug 2012 03:32:44 -0700
From: Josh Triplett <josh@...htriplett.org>
To: Sasha Levin <levinsasha928@...il.com>
Cc: Tejun Heo <tj@...nel.org>, torvalds@...ux-foundation.org,
akpm@...ux-foundation.org, linux-kernel@...r.kernel.org,
linux-mm@...ck.org, paul.gortmaker@...driver.com
Subject: Re: [RFC 1/4] hashtable: introduce a small and naive hashtable
On Thu, Aug 02, 2012 at 12:00:33PM +0200, Sasha Levin wrote:
> On 08/02/2012 12:45 AM, Tejun Heo wrote:
> > On Thu, Aug 02, 2012 at 12:41:56AM +0200, Sasha Levin wrote:
> >> How would your DEFINE_HASHTABLE look like if we got for the simple
> >> 'struct hash_table' approach?
> >
> > I think defining a different enclosing anonymous struct which the
> > requested number of array entries and then aliasing the actual
> > hash_table to that symbol should work. It's rather horrible and I'm
> > not sure it's worth the trouble.
>
> I agree that this is probably not worth the trouble.
>
> At the moment I see two alternatives:
>
> 1. Dynamically allocate the hash buckets.
>
> 2. Use the first bucket to store size. Something like the follows:
>
> #define HASH_TABLE(name, bits) \
> struct hlist_head name[1 << bits + 1];
>
> #define HASH_TABLE_INIT (bits) ({name[0].next = bits});
>
> And then have hash_{add,get} just skip the first bucket.
>
>
> While it's not a pretty hack, I don't see a nice way to avoid having to dynamically allocate buckets for all cases.
What about using a C99 flexible array member? Kernel style prohibits
variable-length arrays, but I don't think the same rationale applies to
flexible array members.
struct hash_table {
size_t count;
struct hlist_head buckets[];
};
#define DEFINE_HASH_TABLE(name, length) struct hash_table name = { .count = length, .buckets = { [0 ... (length - 1)] = HLIST_HEAD_INIT } }
- Josh Triplett
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