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Message-ID: <20131009124310.GA11769@redhat.com>
Date: Wed, 9 Oct 2013 14:43:10 +0200
From: Oleg Nesterov <oleg@...hat.com>
To: Fengguang Wu <fengguang.wu@...el.com>
Cc: Linus Torvalds <torvalds@...ux-foundation.org>,
Peter Zijlstra <peterz@...radead.org>,
Ingo Molnar <mingo@...nel.org>,
Linux Kernel Mailing List <linux-kernel@...r.kernel.org>
Subject: Re: [x86] BUG: unable to handle kernel paging request at 00740060
Hi Fengguang,
On 10/09, Fengguang Wu wrote:
>
> Thanks for looking into this. Attached is the task_work.s for you.
Thanks a lot!
I'm afraid I am wrong, my asm skills are close to zero... but this
code looks wrong to me, and this can explain the oopses.
> task_work_add:
> pushl %ebp #
> movl %esp, %ebp #,
> pushl %edi #
> pushl %esi #
> pushl %ebx #
> subl $12, %esp #,
> call mcount
> movl %eax, %edi # task, task
> movl %edx, -16(%ebp) # work, %sfp
> movb %cl, -21(%ebp) # notify, %sfp
> .p2align 4,,15
> .L3:
> movl 904(%edi), %esi # task_3(D)->task_works, head
> cmpl $work_exited, %esi #, head
> sete %bl #, D.14145
> andl $255, %ebx #, D.14145
> xorl %ecx, %ecx #
> movl %ebx, %edx # D.14145,
> movl $______f.14042, %eax #,
> call ftrace_likely_update #
> testl %ebx, %ebx # D.14145
> jne .L4 #,
> movl -16(%ebp), %edx # %sfp,
> movl %esi, (%edx) # head, work_13(D)->next
> movl %esi, %eax # head, __ret
> #APP
> # 34 "/c/wfg/tip/kernel/task_work.c" 1
> cmpxchgl %edx,904(%edi) #, *__ptr_16
> # 0 "" 2
> #NO_APP
> cmpl %eax, %esi # __ret, head
> jne .L3 #,
OK, we added the new work successfully, we should return 0. If we return
non-zero, fput() (the likely caller) assumes that it should use the workqueues
to close/free this file. Then later task_work_run() will do __fput() again.
> cmpb $0, -21(%ebp) #, %sfp
> je .L5 #,
> movl 4(%edi), %eax # task_3(D)->stack, task_3(D)->stack
> #APP
> # 208 "/c/wfg/tip/arch/x86/include/asm/bitops.h" 1
> bts $1, 8(%eax); jc .L2 #, MEM[(volatile long unsigned int *)D.14203_29],
This is set_notify_resume(). Probably !CONFIG_SMP (I do not see kick_process).
> # 0 "" 2
> #NO_APP
> .L5:
> movl $0, -20(%ebp) #, %sfp
> .L2:
> movl -20(%ebp), %eax # %sfp,
This is what we are going to return. But note that -20(%ebp) was not
initialized if TIF_NOTIFY_RESUME was already set, "jc .L2" skips .L5
above. IOW, in this case we seem to return a random value from stack.
Oleg.
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