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Message-ID: <54921EF2.9070004@intel.com>
Date: Wed, 17 Dec 2014 16:25:22 -0800
From: Dave Hansen <dave.hansen@...el.com>
To: Fenghua Yu <fenghua.yu@...el.com>,
Thomas Gleixner <tglx@...utronix.de>,
"H. Peter Anvin" <hpa@...ux.intel.com>,
Ingo Molnar <mingo@...e.hu>,
Glenn Williamson <glenn.p.williamson@...el.com>
CC: linux-kernel <linux-kernel@...r.kernel.org>, x86 <x86@...nel.org>,
Christoph Lameter <cl@...ux.com>
Subject: Re: [PATCH v2] X86-32: Allocate 256 bytes for pgd in PAE paging
On 12/17/2014 01:47 PM, Fenghua Yu wrote:
> +static inline pgd_t *_pgd_alloc(void)
> +{
> +#if defined(CONFIG_X86_PAE) && !defined(CONFIG_XEN)
> + return kmalloc(sizeof(pgdval_t) * PTRS_PER_PGD, PGALLOC_GFP);
> +#else
> + return (pgd_t *)__get_free_page(PGALLOC_GFP);
> +#endif
> +}
I'm looking at:
"Figure 4-7. Formats of CR3 and Paging-Structure Entries with
PAE Paging"
in the SDM. It makes it pretty clear that the lower 5 bits of cr3 are
ignored in PAE mode. That means we have to be 32-byte (or greater)
aligned, right? Does kmalloc() guarantee that?
IOW, do *ALL* of the sl*b allocators in all of their forms with all of
their debugging options guarantee 32-byte alignment when allocating
256-byte objects?
I know we at least try to align to a cacheline, which would be good
enough, but I'm fuzzy on what we *guarantee*.
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