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Message-ID: <CAMuHMdUFj40OjEHOovFVbtOgr92fJeAq41Hf3h+CqsfPm4aSsQ@mail.gmail.com>
Date: Fri, 8 May 2015 09:07:59 +0200
From: Geert Uytterhoeven <geert@...ux-m68k.org>
To: Lee Jones <lee.jones@...aro.org>
Cc: York Sun <yorksun@...escale.com>,
Julia Lawall <Julia.Lawall@...6.fr>,
Linux I2C <linux-i2c@...r.kernel.org>, wolfram@...-dreams.de,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>
Subject: Re: Why isn't IRQ shared for i2c-ocore
On Fri, May 8, 2015 at 8:57 AM, Lee Jones <lee.jones@...aro.org> wrote:
> On Fri, 08 May 2015, Geert Uytterhoeven wrote:
>
>> On Thu, May 7, 2015 at 9:01 AM, Lee Jones <lee.jones@...aro.org> wrote:
>> >> I have a follow up question regarding interrupt. I see many I2C bus drivers
>> >> request interrupt with flag = 0. Why not using IRQF_SHARED?
>> >
>> > Probably because that particular IRQ is only used by the I2C
>> > Controller. I'm not exactly sure that you're getting at? Why do you
>> > think it should be shared? You should only flag it as shared if it
>> > is.
>>
>> However, that's something the driver can't know.
>> Sharing interrupts is an integration property. The same IP core may share its
>> interrupt on one SoC, and not on another.
>
> I guess that would depend on the IP. If this is part of an MFD, you'd
> know if you only hand a single interrupt line coming into the chip or
> not. If the IP can be moved around (copy & pasted) into different
> chips, then yes, that might change.
>
> How does one share an interrupt with other drivers if all them don't
> know the IRQ is shared thought?
All drivers sharing the same interrupt must pass IRQF_SHARED, cfr. the
checks in __setup_irq().
Traditionally, PC (ISA) drivers didn't share interrupts, as the ISA bus
prohibited interrupt sharing.
Amiga drivers did.
New drivers should support IRQ sharing.
Gr{oetje,eeting}s,
Geert
--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert@...ux-m68k.org
In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
-- Linus Torvalds
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