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Message-ID: <20160113101831.GQ731@pathway.suse.cz>
Date:	Wed, 13 Jan 2016 11:18:31 +0100
From:	Petr Mladek <pmladek@...e.com>
To:	Jacob Pan <jacob.jun.pan@...ux.intel.com>
Cc:	Andrew Morton <akpm@...ux-foundation.org>,
	Oleg Nesterov <oleg@...hat.com>, Tejun Heo <tj@...nel.org>,
	Ingo Molnar <mingo@...hat.com>,
	Peter Zijlstra <peterz@...radead.org>,
	Steven Rostedt <rostedt@...dmis.org>,
	"Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>,
	Josh Triplett <josh@...htriplett.org>,
	Thomas Gleixner <tglx@...utronix.de>,
	Linus Torvalds <torvalds@...ux-foundation.org>,
	Jiri Kosina <jkosina@...e.cz>, Borislav Petkov <bp@...e.de>,
	Michal Hocko <mhocko@...e.cz>, linux-mm@...ck.org,
	Vlastimil Babka <vbabka@...e.cz>, linux-api@...r.kernel.org,
	linux-kernel@...r.kernel.org, Zhang Rui <rui.zhang@...el.com>,
	Eduardo Valentin <edubezval@...il.com>,
	linux-pm@...r.kernel.org
Subject: Re: [PATCH v3 22/22] thermal/intel_powerclamp: Convert the kthread
 to kthread worker API

On Tue 2016-01-12 08:20:21, Jacob Pan wrote:
> On Tue, 12 Jan 2016 11:11:29 +0100
> Petr Mladek <pmladek@...e.com> wrote:
> 
> > > > BTW: I wonder if the original code correctly handle freezing after
> > > > the schedule_timeout(). It does not call try_to_freeze()
> > > > there and the forced idle states might block freezing.
> > > > I think that the small overhead of kthread works is worth
> > > > solving such bugs. It makes it easier to maintain these
> > > > sleeping states.  
> > > it is in a while loop, so try_to_freeze() gets called. Am I missing
> > > something?  
> > 
> > But it might take some time until try_to_freeze() is called.
> > If I get it correctly. try_to_freeze_tasks() wakes freezable
> > tasks to get them into the fridge. If clamp_thread() is waken
> > from that schedule_timeout_interruptible(), it still might inject
> > the idle state before calling try_to_freeze(). It means that freezer
> > needs to wait "quite" some time until the kthread ends up in the
> > fridge.
> > 
> > Hmm, even my conversion does not solve this entirely. We might
> > need to call freezing(current) in the
> > 
> >    while (time_before(jiffies, target_jiffies)) {
> > 
> > cycle. And break injecting the idle state when freezing is requested.
> 
> The injection time for each period is very short, default 6ms. While on
> the other side the default freeze timeout is 20 sec. So I think task
> freeze can wait :)
> i.e.
> unsigned int __read_mostly freeze_timeout_msecs = 20 * MSEC_PER_SEC;

You are right. And it does not make sense to add an extra
freezer-specific code if not really necessary.

Otherwise, I will keep the conversion into the kthread worker as is
for now. Please, let me know if you are strongly against the split
into the two works.


Best Regards,
Petr

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