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Date:   Mon, 1 Jul 2019 15:54:12 +0100
From:   Stefan Hajnoczi <stefanha@...il.com>
To:     Stefano Garzarella <sgarzare@...hat.com>
Cc:     netdev@...r.kernel.org, kvm@...r.kernel.org,
        "Michael S. Tsirkin" <mst@...hat.com>,
        linux-kernel@...r.kernel.org,
        virtualization@...ts.linux-foundation.org,
        Stefan Hajnoczi <stefanha@...hat.com>,
        "David S. Miller" <davem@...emloft.net>
Subject: Re: [PATCH v2 1/3] vsock/virtio: use RCU to avoid use-after-free on
 the_virtio_vsock

On Fri, Jun 28, 2019 at 02:36:57PM +0200, Stefano Garzarella wrote:
> Some callbacks used by the upper layers can run while we are in the
> .remove(). A potential use-after-free can happen, because we free
> the_virtio_vsock without knowing if the callbacks are over or not.
> 
> To solve this issue we move the assignment of the_virtio_vsock at the
> end of .probe(), when we finished all the initialization, and at the
> beginning of .remove(), before to release resources.
> For the same reason, we do the same also for the vdev->priv.
> 
> We use RCU to be sure that all callbacks that use the_virtio_vsock
> ended before freeing it. This is not required for callbacks that
> use vdev->priv, because after the vdev->config->del_vqs() we are sure
> that they are ended and will no longer be invoked.

->del_vqs() is only called at the very end, did you forget to move it
earlier?

In particular, the virtqueue handler callbacks schedule a workqueue.
The work functions use container_of() to get vsock.  We need to be sure
that the work item isn't freed along with vsock while the work item is
still pending.

How do we know that the virtqueue handler is never called in such a way
that it sees vsock != NULL (there is no explicit memory barrier on the
read side) and then schedules a work item after flush_work() has run?

Stefan

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