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Message-ID: <0a957e8d-7af8-613c-11ae-f51b9b241eb7@rasmusvillemoes.dk>
Date: Fri, 20 Dec 2019 09:52:37 +0100
From: Rasmus Villemoes <linux@...musvillemoes.dk>
To: Steven Rostedt <rostedt@...dmis.org>, linux-kernel@...r.kernel.org
Cc: Kirill Tkhai <tkhai@...dex.ru>,
Kirill Tkhai <ktkhai@...tuozzo.com>,
Peter Zijlstra <peterz@...radead.org>,
"mingo@...hat.com" <mingo@...hat.com>,
"juri.lelli@...hat.com" <juri.lelli@...hat.com>,
"vincent.guittot@...aro.org" <vincent.guittot@...aro.org>,
"dietmar.eggemann@....com" <dietmar.eggemann@....com>,
"bsegall@...gle.com" <bsegall@...gle.com>,
"mgorman@...e.de" <mgorman@...e.de>,
Ingo Molnar <mingo@...nel.org>,
Andrew Morton <akpm@...ux-foundation.org>
Subject: Re: [RFC][PATCH 1/4] sched: Force the address order of each sched
class descriptor
On 19/12/2019 22.44, Steven Rostedt wrote:
> From: "Steven Rostedt (VMware)" <rostedt@...dmis.org>
>
> In order to make a micro optimization in pick_next_task(), the order of the
> sched class descriptor address must be in the same order as their priority
> to each other. That is:
>
> &idle_sched_class < &fair_sched_class < &rt_sched_class <
> &dl_sched_class < &stop_sched_class
>
> In order to guarantee this order of the sched class descriptors, add each
> one into their own data section and force the order in the linker script.
I think it would make the code simpler if one reverses these, see other
reply.
> +/*
> + * The order of the sched class addresses are important, as they are
> + * used to determine the order of the priority of each sched class in
> + * relation to each other.
> + */
> +#define SCHED_DATA \
> + *(__idle_sched_class) \
> + *(__fair_sched_class) \
> + *(__rt_sched_class) \
> + *(__dl_sched_class) \
> + STOP_SCHED_CLASS
> +
> /*
> * Align to a 32 byte boundary equal to the
> * alignment gcc 4.5 uses for a struct
> @@ -308,6 +326,7 @@
> #define DATA_DATA \
> *(.xiptext) \
> *(DATA_MAIN) \
> + SCHED_DATA \
> *(.ref.data) \
Doesn't this make the structs end up in .data (writable) rather than
.rodata?
Rasmus
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