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Date:   Sat, 8 May 2021 09:23:55 +0800
From:   Xuewen Yan <xuewen.yan94@...il.com>
To:     Vincent Donnefort <vincent.donnefort@....com>
Cc:     Dietmar Eggemann <dietmar.eggemann@....com>,
        Ingo Molnar <mingo@...hat.com>,
        Peter Zijlstra <peterz@...radead.org>,
        Juri Lelli <juri.lelli@...hat.com>,
        Vincent Guittot <vincent.guittot@...aro.org>,
        Steven Rostedt <rostedt@...dmis.org>,
        Benjamin Segall <bsegall@...gle.com>,
        Mel Gorman <mgorman@...e.de>,
        Daniel Bristot de Oliveira <bristot@...hat.com>,
        linux-kernel <linux-kernel@...r.kernel.org>,
        Chunyan Zhang <zhang.lyra@...il.com>,
        Ryan Y <xuewyan@...mail.com>
Subject: Re: [PATCH v2] sched/pelt: Keep UTIL_AVG_UNCHANGED flag in sync when
 calculating last_enqueued_diff

On Sat, May 8, 2021 at 1:14 AM Vincent Donnefort
<vincent.donnefort@....com> wrote:
>
> [...]
>
> > >
> > > But we take the abs() of last_enqueued_diff.
> > >
> > > If we consider the following examples:
> > >
> > >    enqueued_old = 5, enqueued_new = 9
> > >    diff = 5 - (9 + 1) => 5 - 10 => -5
> > >
> > >    enqueued_old = 9, enqueued_new = 5
> > >    diff = 9 - (5 + 1) => 9 - 6 => 3
> > >
> > > In both cases the delta is supposed to be 4. But in the first case we end-up
> > > with 5. In the second, we end-up with 3. That's why I meant the effect on the
> > > diff depends on who's greater, ue.enqueued or task_util().
> >
> > Ah, OK, due to the abs() in within_margin(). But util's LSB is lost due
> > to the flag anyway. Hence I assume e.g. enqueued_new = 9 should be
> > (task_util() = 8) + 1 (| flag) in the example.
>
> Yeah, I should have used an even number for the demonstration :-)
>
> >
> > OTHA, implementing UTIL_AVG_UNCHANGED as LSB and making this visible on
> > the util_est 'API' has other issues too. The condition
> > `!task_util_est(p)` can never be true in find_energy_efficient_cpu()
> > because of UTIL_AVG_UNCHANGED.
> >
> > So why not use `UTIL_AVG_UNCHANGED = 0x80000000` and just keep its use
> > internal (between cfs_se_util_change() and util_est_update()), i.e. not
> > exporting it (via _task_util_est()) and not eclipsing util_est's LSB
> > value?
>
> As this would be fixing two issues at once, it's probably preferable.
>
> [...]
>
> >  kernel/sched/fair.c |  5 +++--
> >  kernel/sched/pelt.h | 11 ++++++-----
> >  2 files changed, 9 insertions(+), 7 deletions(-)
> >
> > diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
> > index 1d75af1ecfb4..dd30e362c3cc 100644
> > --- a/kernel/sched/fair.c
> > +++ b/kernel/sched/fair.c
> > @@ -3902,7 +3902,7 @@ static inline unsigned long _task_util_est(struct task_struct *p)
> >  {
> >       struct util_est ue = READ_ONCE(p->se.avg.util_est);
> >
> > -     return (max(ue.ewma, ue.enqueued) | UTIL_AVG_UNCHANGED);
> > +     return max(ue.ewma, (ue.enqueued & ~UTIL_AVG_UNCHANGED));
> >  }
> >
> >  static inline unsigned long task_util_est(struct task_struct *p)
> > @@ -4002,7 +4002,7 @@ static inline void util_est_update(struct cfs_rq *cfs_rq,
> >        * Reset EWMA on utilization increases, the moving average is used only
> >        * to smooth utilization decreases.
> >        */
>
> Needs to be updated to add:
>
>         last_enqueued_diff = ue.enqueued & ~UTIL_AVG_UNCHANGED;

The flag had been cleared before, otherwise would return earlier, so
there is no need to clear this flag again.

>
> > -     ue.enqueued = (task_util(p) | UTIL_AVG_UNCHANGED);
> > +     ue.enqueued = task_util(p);
> >       if (sched_feat(UTIL_EST_FASTUP)) {
> >               if (ue.ewma < ue.enqueued) {
> >                       ue.ewma = ue.enqueued;
> > @@ -4051,6 +4051,7 @@ static inline void util_est_update(struct cfs_rq *cfs_rq,
> >       ue.ewma  += last_ewma_diff;
> >       ue.ewma >>= UTIL_EST_WEIGHT_SHIFT;
> >  done:
> > +     ue.enqueued |= UTIL_AVG_UNCHANGED;
> >       WRITE_ONCE(p->se.avg.util_est, ue);
> >
> >       trace_sched_util_est_se_tp(&p->se);
> > diff --git a/kernel/sched/pelt.h b/kernel/sched/pelt.h
> > index 1462846d244e..476faf61f14a 100644

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