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Message-ID: <6a80d9e9-aec9-2cbd-d65b-bb1e84b77b2b@amd.com>
Date:   Tue, 1 Aug 2023 13:51:49 -0500
From:   Mario Limonciello <mario.limonciello@....com>
To:     Linus Torvalds <torvalds@...ux-foundation.org>,
        Jarkko Sakkinen <jarkko@...nel.org>
Cc:     Daniil Stas <daniil.stas@...teo.net>,
        James.Bottomley@...senpartnership.com, Jason@...c4.com,
        linux-integrity@...r.kernel.org, linux-kernel@...r.kernel.org,
        regressions@...mhuis.info, stable@...r.kernel.org
Subject: Re: [PATCH 1/1] tpm: disable hwrng for fTPM on some AMD designs

On 8/1/2023 13:42, Linus Torvalds wrote:
> On Tue, 1 Aug 2023 at 11:28, Jarkko Sakkinen <jarkko@...nel.org> wrote:
>>
>> I would disable it inside tpm_crb driver, which is the driver used
>> for fTPM's: they are identified by MSFT0101 ACPI identifier.
>>
>> I think the right scope is still AMD because we don't have such
>> regressions with Intel fTPM.
> 
> I'm ok with that.
> 
>> I.e. I would move the helper I created inside tpm_crb driver, and
>> a new flag, let's say "TPM_CHIP_FLAG_HWRNG_DISABLED", which tpm_crb
>> sets before calling tpm_chip_register().
>>
>> Finally, tpm_add_hwrng() needs the following invariant:
>>
>>          if (chip->flags & TPM_CHIP_FLAG_HWRNG_DISABLED)
>>                  return 0;
>>
>> How does this sound? I can refine this quickly from my first trial.
> 
> Sounds fine.

This sounds fine by me too, thanks.

> 
> My only worry comes from my ignorance: do these fTPM devices *always*
> end up being enumerated through CRB, or do they potentially look
> "normal enough" that you can actually end up using them even without
> having that CRB driver loaded?
> 
> Put another way: is the CRB driver the _only_ way they are visible, or
> could some people hit on this through the TPM TIS interface if they
> have CRB disabled?
> 
> I see, for example, that qemu ends up emulating the TIS layer, and it
> might end up forwarding the TPM requests to something that is natively
> CRB?
> 
> But again: I don't know enough about CRB vs TIS, so the above may be a
> stupid question.
> 
>             Linus

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