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Message-ID: <ZN8yE7jsI3z63EEw@smile.fi.intel.com>
Date: Fri, 18 Aug 2023 11:55:47 +0300
From: Andy Shevchenko <andriy.shevchenko@...ux.intel.com>
To: Rasmus Villemoes <linux@...musvillemoes.dk>
Cc: Yury Norov <yury.norov@...il.com>, linux-kernel@...r.kernel.org
Subject: Re: [PATCH v1 2/2] bitmap: Optimize memset() calls
On Fri, Aug 18, 2023 at 08:53:38AM +0200, Rasmus Villemoes wrote:
> On 17/08/2023 18.54, Andy Shevchenko wrote:
...
> > +#if BITS_PER_LONG == 64
> > + memset64((uint64_t *)dst, 0, len);
> > +#else
> > + memset32((uint32_t *)dst, 0, len);
> > +#endif
> > }
>
> So _if_ this is worth it at all,
Yury, I believe you have a set of performance tests for bitmaps, perhaps you
can give a try and see if we got a benefit here.
Yet, not all architectures have custom implementation of the optimized
memset()/memcpy(). But at least ARM, x86 do.
> all those new '#if BITS_PER_LONG == 64'
> suggests that we should instead have a new helper memset_long(), no?
>
> In fact, string.h already has that:
>
> static inline void *memset_l(unsigned long *p, unsigned long v,
> __kernel_size_t n)
My grep skills suddenly degraded, my thoughts were exactly like yours,
but I missed the _l instead of _long for which I grepped.
...
> Please just spell an all-ones long "~0UL", that also matches the
> small_const case.
OK!
...
> > - memset(&dst[lim - off], 0, off*sizeof(unsigned long));
> > + bitmap_zero(&dst[lim - off], off);
>
> This... can't be right.
Indeed, I have in mind memset_long() and on the half-way replaced it with
bitmap_zero().
> bitmap_zero() still takes an argument which is
> the size in bits, while off is the whole number of words to shift. So if
> called with say shift=128, we'd have off==2, and that bitmap_zero()
> would, because bitmap_zero() rounds up to a whole number of words, end
> up clearing just one word.
>
> Perhaps a chance to add some more test cases? Maybe we're not exercising
> any of the "shift more than BITS_PER_LONG" logic.
>
> But rather than using bitmap_zero() here, forcing you to convert off to
> a number of bits and then bitmap_zero to divide again, if you do this at
> all, just change that memset() to memset_l().
Agree.
--
With Best Regards,
Andy Shevchenko
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