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Message-ID: <ZO9hrc2KDUOfbQm1@chenyu5-mobl2>
Date: Wed, 30 Aug 2023 23:35:09 +0800
From: Chen Yu <yu.c.chen@...el.com>
To: Shrikanth Hegde <sshegde@...ux.vnet.ibm.com>
CC: Ingo Molnar <mingo@...hat.com>, Juri Lelli <juri.lelli@...hat.com>,
"Tim Chen" <tim.c.chen@...el.com>,
Mel Gorman <mgorman@...hsingularity.net>,
Dietmar Eggemann <dietmar.eggemann@....com>,
K Prateek Nayak <kprateek.nayak@....com>,
"Gautham R . Shenoy" <gautham.shenoy@....com>,
Chen Yu <yu.chen.surf@...il.com>,
Aaron Lu <aaron.lu@...el.com>, <linux-kernel@...r.kernel.org>,
Peter Zijlstra <peterz@...radead.org>,
Vincent Guittot <vincent.guittot@...aro.org>
Subject: Re: [RFC PATCH 5/7] sched/fair: Adjust the busiest group scanning
depth in idle load balance
On 2023-08-25 at 11:30:05 +0530, Shrikanth Hegde wrote:
>
>
> On 7/27/23 8:05 PM, Chen Yu wrote:
> > Scanning the whole sched domain to find the busiest group is time costly
> > during newidle_balance(). And if a CPU becomes idle, it would be good
> > if this idle CPU pulls some tasks from other CPUs as quickly as possible.
> >
> > Limit the scan depth of newidle_balance() to only scan for a limited number
> > of sched groups to find a relatively busy group, and pull from it.
> > In summary, the more spare time there is in the domain, the more time
> > each newidle balance can spend on scanning for a busy group. Although
> > the newidle balance has per domain max_newidle_lb_cost to decide
> > whether to launch the balance or not, the ILB_UTIL provides a smaller
> > granularity to decide how many groups each newidle balance can scan.
> >
> > The scanning depth is calculated by the previous periodic load balance
> > based on its overall utilization.
> >
> > Tested on top of v6.5-rc2, Sapphire Rapids with 2 x 56C/112T = 224 CPUs.
> > With cpufreq governor set to performance, and C6 disabled.
> >
> > Firstly, tested on a extreme synthetic test[1], which launches 224
> > process. Each process is a loop of nanosleep(1 us), which is supposed
> > to trigger newidle balance as much as possible:
> >
> > i=1;while [ $i -le "224" ]; do ./nano_sleep 1000 & i=$(($i+1)); done;
> >
> > NO_ILB_UTIL + ILB_SNAPSHOT:
> > 9.38% 0.45% [kernel.kallsyms] [k] newidle_balance
> > 6.84% 5.32% [kernel.kallsyms] [k] update_sd_lb_stats.constprop.0
> >
> > ILB_UTIL + ILB_SNAPSHOT:
> > 3.35% 0.38% [kernel.kallsyms] [k] newidle_balance
> > 2.30% 1.81% [kernel.kallsyms] [k] update_sd_lb_stats.constprop.0
> > [...]
>
> > Link: https://raw.githubusercontent.com/chen-yu-surf/tools/master/stress_nanosleep.c #1
> > Suggested-by: Tim Chen <tim.c.chen@...el.com>
> > Signed-off-by: Chen Yu <yu.c.chen@...el.com>
> > ---
> > kernel/sched/fair.c | 20 +++++++++++++++++++-
> > 1 file changed, 19 insertions(+), 1 deletion(-)
> >
> > diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
> > index 6925813db59b..4e360ed16e14 100644
> > --- a/kernel/sched/fair.c
> > +++ b/kernel/sched/fair.c
> > @@ -10195,7 +10195,13 @@ static inline void update_sd_lb_stats(struct lb_env *env, struct sd_lb_stats *sd
> > struct sg_lb_stats *local = &sds->local_stat;
> > struct sg_lb_stats tmp_sgs;
> > unsigned long sum_util = 0;
> > - int sg_status = 0;
> > + int sg_status = 0, nr_sg_scan;
> > + /* only newidle CPU can load the snapshot */
> > + bool ilb_can_load = env->idle == CPU_NEWLY_IDLE &&
> > + sd_share && READ_ONCE(sd_share->total_capacity);
> > +
> > + if (sched_feat(ILB_UTIL) && ilb_can_load)
>
> Suggestion for small improvement:
>
> it could be ? This could help save a few cycles of checking if the feature is enabled when its not newidle.
>
> if ( ilb_can_load && sched_feat(ILB_UTIL))
>
> Same comments below in this patch as well in PATCH 6/7.
>
Yes this makes sense because the feature is enabled by default.
> > + nr_sg_scan = sd_share->nr_sg_scan;
> >
> > do {
> > struct sg_lb_stats *sgs = &tmp_sgs;
> > @@ -10222,6 +10228,9 @@ static inline void update_sd_lb_stats(struct lb_env *env, struct sd_lb_stats *sd
> > sds->busiest_stat = *sgs;
> > }
> >
> > + if (sched_feat(ILB_UTIL) && ilb_can_load && --nr_sg_scan <= 0)
> > + goto load_snapshot;
> > +
>
> Same comment as above.
>
OK, will do.
thanks,
Chenyu
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