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Message-ID: <ZRL3mlWXqseER8xK@Boquns-Mac-mini.home>
Date: Tue, 26 Sep 2023 08:24:10 -0700
From: Boqun Feng <boqun.feng@...il.com>
To: Gary Guo <gary@...yguo.net>
Cc: Benno Lossin <benno.lossin@...ton.me>, Alice Ryhl <alice@...l.io>,
Alice Ryhl <aliceryhl@...gle.com>,
Wedson Almeida Filho <wedsonaf@...il.com>,
rust-for-linux@...r.kernel.org, Miguel Ojeda <ojeda@...nel.org>,
Alex Gaynor <alex.gaynor@...il.com>,
Björn Roy Baron <bjorn3_gh@...tonmail.com>,
Andreas Hindborg <a.hindborg@...sung.com>,
linux-kernel@...r.kernel.org,
Wedson Almeida Filho <walmeida@...rosoft.com>
Subject: Re: [PATCH v2 2/2] rust: arc: remove `ArcBorrow` in favour of
`WithRef`
On Tue, Sep 26, 2023 at 04:26:59PM +0800, Gary Guo wrote:
> On Mon, 25 Sep 2023 22:26:56 +0000
> Benno Lossin <benno.lossin@...ton.me> wrote:
>
[...]
> >
> > The pointer was originally derived by a call to `into_raw`:
> > ```
> > pub fn into_raw(self) -> *const T {
> > let ptr = self.ptr.as_ptr();
> > core::mem::forget(self);
> > // SAFETY: The pointer is valid.
> > unsafe { core::ptr::addr_of!((*ptr).data) }
> > }
> > ```
> > So in this function the origin (also the origin of the provenance)
> > of the pointer is `ptr` which is of type `NonNull<WithRef<T>>`.
> > Raw pointers do not lose this provenance information when you cast
> > it and when using `addr_of`/`addr_of_mut`. So provenance is something
> > that is not really represented in the type system for raw pointers.
> >
> > When doing a round trip through a reference though, the provenance is
> > newly assigned and thus would only be valid for a `T`:
> > ```
> > let raw = arc.into_raw();
> > let reference = unsafe { &*raw };
> > let raw: *const T = reference;
> > let arc = unsafe { Arc::from_raw(raw) };
> > ```
> > Miri would complain about the above code.
> >
>
> One thing we can do is to opt from strict provenance, so:
>
A few questions about strict provenance:
> ```
> let raw = arc.into_raw();
> let _ = raw as usize; // expose the provenance of raw
Should this be a expose_addr()?
> let reference = unsafe { &*raw };
> let raw = reference as *const T as usize as *const T;
and this is a from_exposed_addr{_mut}(), right?
> let arc = unsafe { Arc::from_raw(raw) };
> ```
>
One step back, If we were to use strict provenance API (i.e.
expose_addr()/from_exposed_addr()), we could use it to "fix" the
original problem? By:
* expose_addr() in as_with_ref()
* from_exposed_addr() in `impl From<&WithRef<T>> for Arc`
right?
More steps back, is the original issue only a real issue under strict
provenance rules? Don't make me wrong, I like the ideas behind strict
provenance, I just want to check, if we don't enable strict provenance
(as a matter of fact, we don't do it today), will the original issue
found by Alice be a UB? Or is there a way to disable Miri's check on
strict provenance? IIUC, the cause of the original issue is that "you
cannot reborrow a pointer derived from a `&` to get a `&mut`, even when
there is no other alias to the same object". Maybe I'm still missing
something, but without strict provenance, is this a problem? Or is there
a provenance model of Rust without strict provenance?
Regards,
Boqun
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