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Message-ID: <ZbwSxGpySa8RBt9A@boqun-archlinux>
Date: Thu, 1 Feb 2024 13:53:08 -0800
From: Boqun Feng <boqun.feng@...il.com>
To: Bart Van Assche <bvanassche@....org>
Cc: Zhiguo Niu <zhiguo.niu@...soc.com>, peterz@...radead.org,
mingo@...hat.com, will@...nel.org, longman@...hat.com,
linux-kernel@...r.kernel.org, niuzhiguo84@...il.com,
ke.wang@...soc.com, xuewen.yan@...soc.com,
Carlos Llamas <cmllamas@...gle.com>
Subject: Re: [PATCH V2] lockdep: fix deadlock issue between lockdep and rcu
On Thu, Feb 01, 2024 at 12:56:36PM -0800, Bart Van Assche wrote:
> On 2/1/24 11:58, Boqun Feng wrote:
> > On Thu, Feb 01, 2024 at 09:22:20AM -0800, Bart Van Assche wrote:
> > > On 1/16/24 23:48, Zhiguo Niu wrote:
> > > > /*
> > > > - * If there's anything on the open list, close and start a new callback.
> > > > - */
> > > > - call_rcu_zapped(delayed_free.pf + delayed_free.index);
> > > > + * If there's anything on the open list, close and start a new callback.
> > > > + */
> > > > + if (need_callback)
> > > > + call_rcu(&delayed_free.rcu_head, free_zapped_rcu);
> > >
> > > The comment above the if-statement refers to the call_rcu_zapped() function
> > > while call_rcu_zapped() has been changed into call_rcu(). So the comment is
> > > now incorrect.
> > >
> > > Additionally, what guarantees that the above code won't be triggered
> > > concurrently from two different threads? As you may know calling call_rcu()
> > > twice before the callback has been started is not allowed. I think that can
> > > happen with the above code.
> >
> > No, it's synchronized by the delayed_free.schedule. Only one thread/CPU
> > can schedule at a time. Or am I missing something subtle?
>
> Only call_rcu_zapped() reads and modifies delayed_free.scheduled. Direct
> call_rcu() calls do neither read nor modify delayed_free.scheduled.
Have you checked the change in the patch? Now call_rcu_zapped() has been
splitted into two parts: preparing the callback and calling call_rcu(),
the preparing part checks and sets the delayed_free.scheduled under
graph_lock(), so only one CPU/thread will win and do the actual
call_rcu(). And the RCU callback free_zapped_rcu() will unset
delayed_free.scheduled, again under graph_lock().
If you think it's still possible, could you provide a case where the
race may happen?
Regards,
Boqun
>
> Bart.
>
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