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Message-ID: <f0e4c51c-8227-4f5c-876f-38fbb4a0e1bf@linux.ibm.com>
Date: Thu, 13 Jun 2024 10:26:11 +0530
From: Nilay Shroff <nilay@...ux.ibm.com>
To: Keith Busch <kbusch@...a.com>, linux-nvme@...ts.infradead.org,
linux-kernel@...r.kernel.org, linux-kselftest@...r.kernel.org
Cc: hch@....de, sagi@...mberg.me, paulmck@...nel.org, davidgow@...gle.com,
akpm@...ux-foundation.org, venkat88@...ux.vnet.ibm.com,
Keith Busch <kbusch@...nel.org>
Subject: Re: [PATCH 1/2] list: introduce a new cutting helper
On 6/12/24 21:21, Keith Busch wrote:
> From: Keith Busch <kbusch@...nel.org>
>
> Provide a helper to remove elements from a list to the end, and place
> those elements in a new list.
>
> Signed-off-by: Keith Busch <kbusch@...nel.org>
> ---
> include/linux/list.h | 20 ++++++++++++++++++++
> lib/list-test.c | 29 +++++++++++++++++++++++++++++
> 2 files changed, 49 insertions(+)
>
> diff --git a/include/linux/list.h b/include/linux/list.h
> index 5f4b0a39cf46a..f22850e854820 100644
> --- a/include/linux/list.h
> +++ b/include/linux/list.h
> @@ -520,6 +520,26 @@ static inline void list_cut_before(struct list_head *list,
> entry->prev = head;
> }
>
> +/**
> + * list_cut - cut a list into two from the entry
> + * @list: a new list to add all removed entries
> + * @head: a list with entries
> + * @entry: an entry within head, could be the head itself
> + *
> + * This helper removes elements from @head starting at @entry until the end,
> + * and appends them to @lists.
> + */
> +static inline void list_cut(struct list_head *list,
> + struct list_head *head, struct list_head *entry)
> +{
> + list->next = entry;
> + list->prev = head->prev;
> + head->prev = entry->prev;
> + entry->prev->next = head;
> + entry->prev = list;
> + list->prev->next = list;
> +}
I am wondering whether we really need the _rcu version of list_cut here?
I think that @head could point to an _rcu protected list and that's true
for this patch. So there might be concurrent readers accessing @head using
_rcu list-traversal primitives, such as list_for_each_entry_rcu().
An _rcu version of list_cut():
static inline void list_cut_rcu(struct list_head *list,
struct list_head *head, struct list_head *entry)
{
list->next = entry;
list->prev = head->prev;
head->prev = entry->prev;
rcu_assign_pointer(list_next_rcu(entry->prev), head);
entry->prev = list;
list->prev->next = list;
}
Thanks,
--Nilay
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