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Message-ID: <Z79JyhOQUI_LV4oV@blossom>
Date: Wed, 26 Feb 2025 12:05:14 -0500
From: Alyssa Rosenzweig <alyssa@...enzweig.io>
To: Sven Peter <sven@...npeter.dev>
Cc: Janne Grunau <j@...nau.net>, asahi@...ts.linux.dev,
	linux-arm-kernel@...ts.infradead.org, linux-kernel@...r.kernel.org,
	Hector Martin <marcan@...can.st>
Subject: Re: [PATCH 2/4] soc: apple: rtkit: Implement OSLog buffers properly

> >> +	if (ep == APPLE_RTKIT_EP_OSLOG) {
> >> +		buffer->size = FIELD_GET(APPLE_RTKIT_OSLOG_SIZE, msg);
> >> +		buffer->iova = FIELD_GET(APPLE_RTKIT_OSLOG_IOVA, msg) << 12;
> >> +	} else {
> >> +		buffer->size = FIELD_GET(APPLE_RTKIT_BUFFER_REQUEST_SIZE, msg) << 12;
> >> +		buffer->iova = FIELD_GET(APPLE_RTKIT_BUFFER_REQUEST_IOVA, msg);
> >> +	}
> >
> > The shifts are suspiciously asymmetric. Are we really sure this is
> > correct? My guess is that both size & iova for both oslog & buffer need
> > to be page-aligned, so all 4 lines should be shifted, and the bit
> > offsets should be adjusted in turn, and the lower 12-bits in oslog_size
> > and buffer_iova are reserved. But that's just a guess.
> >
> > Anyway if this logic is really what we want it deserves a comment
> > because it looks like a typo.
> 
> That guess can't be true for syslog since there's no change in behavior here
> and the syslog endpoint has been working fine so far. This common code is
> also used for other endpoints that request buffers and there haven't been
> any issues there either. The size is just passed in "number of 4k chunks"
> and the IOVA needs no additional fixups.
> 
> 
> The entire reason for this commit is because this common logic just didn't
> work for oslog. Our u-boot fork uses the same logic as used here [1]. We're stealing
> a chunk of MTP's SRAM to make hand-off to Linux easier there. If either size or
> IOVA was off by a factor 0x4000 this would've never worked in the first
> place.

I'm not suggesting things are off by a factor of 4k. Rather I'm
questioning what the behaviour is when we're not 4k aligned. (I.e.
the syslog or oslog buffer does not both start and end at 4k
boundaries.)

If we're aligned, all our bottom bits are 0, and hypothetically we're
putting 0 into "reserved-must be zero" bits.

I guess it's inconsequential if everything is 4k aligned in practice.
But .. is it? I don't know.

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