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Message-ID: <20070103185203.2754e059@griffin.suse.cz>
Date: Wed, 3 Jan 2007 18:52:03 +0100
From: Jiri Benc <jbenc@...e.cz>
To: Jan Kiszka <jan.kiszka@....de>
Cc: netdev@...r.kernel.org, Ivo Van Doorn <ivdoorn@...il.com>,
rt2400-devel@...ts.sourceforge.net
Subject: Re: d80211: How does TX flow control work?
On Tue, 02 Jan 2007 14:08:21 +0100, Jan Kiszka wrote:
> What I (think to) understand is that a low-level drivers call
> ieee80211_stop_queue() if they run out of buffers. That flips a
> per-queue bit (IEEE80211_LINK_STATE_XOFF), prevents that any further
> frame is passed to the low-level TX routine,
Correct.
> and can cause that up to
> *one* packet per queue is stored in
> ieee80211_local::pending_packets[queue].
This is needed due to fragmented frames. After resume, passing of
fragments to the driver has to continue where it was stopped. Returning
the half-sent fragmented frame to the 802.11 qdisc wasn't possible
until recently (I think the conversion of master interface to native
802.11 type could allow that now - but it's probably not worth the
effort).
> But it looks to me like nothing
> prevents ieee80211_tx() being invoked even in case that there is already
> some stuff in that single-packet storage.
The 802.11 qdisc (see wme_qdiscop_dequeue) takes care of that.
> That in turn triggers WARN_ONs in ieee80211_tx() under high load for me
> (with rt2500usb). And it should also cause orphaned skbs because the
> storage is overwritten in that case. Either I'm blind or something is
> fishy...
You are most likely hitting some bug. Could you post more information
please?
Thanks,
Jiri
--
Jiri Benc
SUSE Labs
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