[<prev] [next>] [<thread-prev] [thread-next>] [day] [month] [year] [list]
Message-ID: <20100630023718.GU2138@verge.net.au>
Date: Wed, 30 Jun 2010 11:37:18 +0900
From: Simon Horman <horms@...ge.net.au>
To: ratheesh k <ratheesh.ksz@...il.com>
Cc: Netfilter mailing list <netfilter@...r.kernel.org>,
netdev@...r.kernel.org
Subject: Re: nat bypass
On Mon, Jun 28, 2010 at 03:43:46PM +0530, ratheesh k wrote:
> Hi,
>
> A -------> R ------->S
>
> I have a linux machine A is connected to Linux machine R . Machine R
> is having two network interfaces and acting as a router .
> It has a dhcp server running . It will assign ip in 192.168.1.0/24
> subnet to all machine connected on lan side ( A is connected also in
> lan side ) . Wan side of R is connected to HTTP server S . There is
> also a DHCP server running on S to assign ip in 10.232.18.0/24 subnet
> . Is there any way , in which NAT should be bypassed to get ip from
> DHCP server running on S . My question is : How can A will get an ip
> from 10.232.18.0/24 pool ip .?
> ebtables is an option ? How can we make it ?
> Is there any other optimal way ?
Let me try and understand this.
R is routing between 192.168.1.0/24 and 10.232.18.0/24.
As A is on the 192.168.1.0/24 side of R.
But to give A an 10.232.18.0/24 address (dynamically)?
Why?
--
To unsubscribe from this list: send the line "unsubscribe netdev" in
the body of a message to majordomo@...r.kernel.org
More majordomo info at http://vger.kernel.org/majordomo-info.html
Powered by blists - more mailing lists