netdev - Re: nat bypass

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Message-ID: <AANLkTilxqHHiDfzQbewBe8cnTtvdB9CCTPn9EVCcAf5Q@mail.gmail.com>
Date:	Wed, 30 Jun 2010 14:54:32 +0530
From:	ratheesh k <ratheesh.ksz@...il.com>
To:	Simon Horman <horms@...ge.net.au>
Cc:	Netfilter mailing list <netfilter@...r.kernel.org>,
	netdev@...r.kernel.org
Subject: Re: nat bypass

> Let me try and understand this.
>
> R is routing between 192.168.1.0/24 and 10.232.18.0/24.
> As A is on the 192.168.1.0/24 side of R.
> But to give A an 10.232.18.0/24 address (dynamically)?
>
> Why?
>

For some clients , R should act as a mere bridge , Not a router .


On Wed, Jun 30, 2010 at 8:07 AM, Simon Horman <horms@...ge.net.au> wrote:
> On Mon, Jun 28, 2010 at 03:43:46PM +0530, ratheesh k wrote:
>> Hi,
>>
>>   A -------> R ------->S
>>
>> I have a linux machine A is connected to Linux machine R . Machine R
>> is having two network interfaces and acting as a router .
>> It has a dhcp server running  . It will assign ip in 192.168.1.0/24
>> subnet to all machine connected on lan side ( A is connected also in
>> lan side ) . Wan side of R is connected to HTTP server S . There is
>> also a DHCP server running on S to assign ip in 10.232.18.0/24 subnet
>> .  Is there any way , in which NAT should be bypassed to get ip from
>> DHCP server running  on S . My question is : How can A will get  an ip
>> from 10.232.18.0/24 pool ip .?
>> ebtables is an option ? How can we make it ?
>> Is there any other optimal way ?
>
> Let me try and understand this.
>
> R is routing between 192.168.1.0/24 and 10.232.18.0/24.
> As A is on the 192.168.1.0/24 side of R.
> But to give A an 10.232.18.0/24 address (dynamically)?
>
> Why?
>
>
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