netdev - Re: nat bypass

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Date:	Wed, 30 Jun 2010 08:05:45 -0400
From:	Stephen Clark <sclark46@...thlink.net>
To:	ratheesh k <ratheesh.ksz@...il.com>
CC:	Simon Horman <horms@...ge.net.au>,
	Netfilter mailing list <netfilter@...r.kernel.org>,
	netdev@...r.kernel.org
Subject: Re: nat bypass

On 06/30/2010 05:24 AM, ratheesh k wrote:
>> Let me try and understand this.
>>
>> R is routing between 192.168.1.0/24 and 10.232.18.0/24.
>> As A is on the 192.168.1.0/24 side of R.
>> But to give A an 10.232.18.0/24 address (dynamically)?
>>
>> Why?
>>
>
> For some clients , R should act as a mere bridge , Not a router .
>
>
> On Wed, Jun 30, 2010 at 8:07 AM, Simon Horman<horms@...ge.net.au>  wrote:
>> On Mon, Jun 28, 2010 at 03:43:46PM +0530, ratheesh k wrote:
>>> Hi,
>>>
>>>    A ------->  R ------->S
>>>
>>> I have a linux machine A is connected to Linux machine R . Machine R
>>> is having two network interfaces and acting as a router .
>>> It has a dhcp server running  . It will assign ip in 192.168.1.0/24
>>> subnet to all machine connected on lan side ( A is connected also in
>>> lan side ) . Wan side of R is connected to HTTP server S . There is
>>> also a DHCP server running on S to assign ip in 10.232.18.0/24 subnet
>>> .  Is there any way , in which NAT should be bypassed to get ip from
>>> DHCP server running  on S . My question is : How can A will get  an ip
>>> from 10.232.18.0/24 pool ip .?
>>> ebtables is an option ? How can we make it ?
>>> Is there any other optimal way ?
>>
>> Let me try and understand this.
>>
>> R is routing between 192.168.1.0/24 and 10.232.18.0/24.
>> As A is on the 192.168.1.0/24 side of R.
>> But to give A an 10.232.18.0/24 address (dynamically)?
>>
>> Why?
>>
>>
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>
Will dhcprelay work for you?

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