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Message-ID: <4244fe46-e8ed-9fd2-d243-cc84e7264a88@c-s.fr>
Date: Wed, 29 Aug 2018 09:18:01 +0200
From: Christophe LEROY <christophe.leroy@....fr>
To: Qiang Zhao <qiang.zhao@....com>,
David Gounaris <david.gounaris@...inera.com>,
"netdev@...r.kernel.org" <netdev@...r.kernel.org>,
"linuxppc-dev@...ts.ozlabs.org" <linuxppc-dev@...ts.ozlabs.org>
Subject: Re: [PATCH 4/6] net/wan/fsl_ucc_hdlc: default hmask value
Le 29/08/2018 à 04:54, Qiang Zhao a écrit :
> From: David Gounaris <david.gounaris@...inera.com>
> Date: 2018/8/28 19:09
>> Subject: [PATCH 4/6] net/wan/fsl_ucc_hdlc: default hmask value
>>
>> Set default HMASK to 0x0000 to use
>> promiscuous mode in the hdlc controller.
Why do you need to do that ?
An HDLC frame encapsulating Ethernet should look like:
HDLC Frame includes:
– Opening Flag 7E hex
– Address field FF hex
– Control field 03 hex
– Information field Original Ethernet Packet, 1522 octets max.
– FCS CRC16 (2 bytes)
– Closing Flag 7E hex
What do you mean by 'promiscuous mode' ?
In any case, should a filter mask be changed for promiscuous mode, I
believe the change should be done at the time you enter promiscuous
mode, not at all time.
Christophe
>>
>> Signed-off-by: David Gounaris <david.gounaris@...inera.com>
>> ---
>> drivers/net/wan/fsl_ucc_hdlc.h | 2 +-
>> 1 file changed, 1 insertion(+), 1 deletion(-)
>>
>> diff --git a/drivers/net/wan/fsl_ucc_hdlc.h b/drivers/net/wan/fsl_ucc_hdlc.h
>> index c21134c1f180..5bc3d1a6ca6e 100644
>> --- a/drivers/net/wan/fsl_ucc_hdlc.h
>> +++ b/drivers/net/wan/fsl_ucc_hdlc.h
>> @@ -134,7 +134,7 @@ struct ucc_hdlc_private {
>>
>> #define HDLC_HEAD_MASK 0x0000
>> #define DEFAULT_HDLC_HEAD 0xff44
>> -#define DEFAULT_ADDR_MASK 0x00ff
>> +#define DEFAULT_ADDR_MASK 0x0000
>> #define DEFAULT_HDLC_ADDR 0x00ff
>>
>> #define BMR_GBL 0x20000000
>> --
>
> It is not proper to set default HMASK to 0x0000, how about to add a new property standing for hmask into device tree,
> If get this property from dtb, then set it with the value from dtb, otherwise, set it with default HMASK ox00ff?
>
> Best Regards
> Qiang Zhao
>
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