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Message-ID: <4F4BAD5E.9000600@parallels.com>
Date: Mon, 27 Feb 2012 20:20:46 +0400
From: Stanislav Kinsbursky <skinsbursky@...allels.com>
To: David Laight <David.Laight@...LAB.COM>
CC: "Trond.Myklebust@...app.com" <Trond.Myklebust@...app.com>,
"linux-nfs@...r.kernel.org" <linux-nfs@...r.kernel.org>,
Pavel Emelianov <xemul@...allels.com>,
"neilb@...e.de" <neilb@...e.de>,
"netdev@...r.kernel.org" <netdev@...r.kernel.org>,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
James Bottomley <jbottomley@...allels.com>,
"bfields@...ldses.org" <bfields@...ldses.org>,
"davem@...emloft.net" <davem@...emloft.net>,
"devel@...nvz.org" <devel@...nvz.org>
Subject: Re: [PATCH v2 2/4] NFS: release per-net clients lock before calling
PipeFS dentries creation
27.02.2012 19:59, David Laight пишет:
>
>> spin_lock(&nn->nfs_client_lock);
>> - list_for_each_entry(clp,&nn->nfs_client_list, cl_share_link) {
>> + list_for_each_entry_safe(clp, tmp,&nn->nfs_client_list,
> cl_share_link) {
>> if (clp->rpc_ops !=&nfs_v4_clientops)
>> continue;
>> + atomic_inc(&clp->cl_count);
>> + spin_unlock(&nn->nfs_client_lock);
>> error = __rpc_pipefs_event(clp, event, sb);
>> + nfs_put_client(clp);
>> if (error)
>> break;
>> + spin_lock(&nn->nfs_client_lock);
>> }
>> spin_unlock(&nn->nfs_client_lock);
>> return error;
>
> The locking doesn't look right if the loop breaks on error.
> (Same applied to patch v2 1/4)
>
Thanks for the catch. I'll fix this.
> Although list_fo_each_entry_safe() allows the current entry
> to be freed, I don't believe it allows the 'next' to be freed.
> I doubt there is protection against that happening.
>
We need to use safe macro, because client can be destroyed on nfs_put_client() call.
About "protection against ... the 'next' to be freed" - I dont' think, that we
need any protection against it. This will be done under nfs_client_lock, and
current entry list pointers will be updated properly.
> Do you need to use an atomic_inc() for cl_count.
> I'd guess the nfs_client_lock is usually held?
>
Sorry, I don't understand this question.
--
Best regards,
Stanislav Kinsbursky
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